X.

Exercise 52.

Solve:

1. $\frac{2}{3}(x+1)-\frac{1}{7}(x+5)=1$.

2. $\frac{6}{7}(x-9)-\frac{1}{3}(5-x)+3x+1=0$.

3. $\frac{1}{3}(5x-24)+\frac{1}{7}(x-2)-2(x-1)=0$.

4. ${\displaystyle \frac{x+3}{4}}+{\displaystyle \frac{7x-2}{5}}={\displaystyle \frac{5x-1}{4}}+{\displaystyle \frac{5x+4}{9}}$.

5. ${\displaystyle \frac{x+1}{3}}-{\displaystyle \frac{x-1}{4}}={\displaystyle \frac{x-2}{5}}-{\displaystyle \frac{x-3}{6}}+{\displaystyle \frac{31}{60}}$.

6. ${\displaystyle \frac{(2x-1)(2-x)}{2}}+x^2-{\displaystyle \frac{1+3x}{2}}=0$.

7. ${\displaystyle \frac{6x-11}{4}}-{\displaystyle \frac{3-4x}{6}}={\displaystyle \frac{4}{3}}-{\displaystyle \frac{x}{8}}$.

8. ${\displaystyle \frac{x+6}{4}}-{\displaystyle \frac{16-3x}{12}}=4\frac{1}{6}$.

9. $x-{\displaystyle \frac{x-2}{3}}={\displaystyle \frac{x+23}{4}}-{\displaystyle \frac{10+x}{5}}$.

5 x + 3 x − 1 + 2 x − 3 2 x − 1 = 6