A - a = b - A, lintwhence A = a + b2. rintFormula (2)
Hence, the arithmetical mean of any two numbers is found by taking half their sum.
Sometimes it is required to insert several arithmetical means between two numbers.
If the number of means, and the whole number of terms, then . If is substituted for in formula (1),
l = a + (n - 1)d, lintthe result is l = a + (m + 1)d. [1] lint By transposing , l - a = (m + 1) d. l - am + 1 = d. Formula (3)
Thus, if it be required to insert six means between and , the value of is found to be ; and the series will be , , , , , , , .
Exercise 75.
- Find the 25th term in the series , , , .
- Find the 13th term in the series , , , .
- Find the 15th term in the series , , , .
- Find the 19th term in the series , , , .
- Find the 10th term in an arithmetical progression whose 1st term is and 3d term .
- Find the 11th term in an arithmetical progression whose 1st term is and whose 6th term is .
- If the 3d term of an arithmetical progression is and the 13th term is , what is the 20th term?
- Which term of the series , , , , , is ?
- Which term of the series , , , , is ?
- What is the arithmetical mean of and ?
- What is the arithmetical mean of and ?
- Insert arithmetical means between and .
171. To Find the Sum of Any Number of Terms of an Arithmetical Series.
If denote the last term, the first term, the number of terms, the common difference, and the sum of the terms, it is evident that the series beginning with the first term will be , , , etc., and beginning with the last term will be , , , etc. Therefore,
{r*{12}{c}} s &=& a &+& (a + d) &+& (a + 2d) &+& \dots &+& (l - d) &+& l, \rlap{\quad\text{or}} \ s &=& l &+& (l - d) &+& (l - 2d) &+& \dots &+& (a + d) &+& a \ \hline 2s &=& (a + l) &+& (a + l) &+&