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nydus/The First Steps in AlgebraPublic
Page 77 of 226
Table of Contents

Case III.

Therefore a2−(3b−5c)2=(a+3b−5c)(a−3b+5c).

Exercise 34.

Resolve into factors:

  1. (x+y)2−z2.
  1. (x−y)2−z2.
  1. z2−(x+y)2.
  1. z2−(x−y)2.
  1. (x+y)2−4z2.
  1. 4z2−(x−y)2.
  1. (a+2b)2−c2.
  1. (a−2b)2−c2.
  1. c2−(a−2b)2.
  1. (2a+5c)2−1.
  1. 1−(2a−5c)2.
  1. (a+3b)2−16c2.
  1. (a−5b)2−9c2.
  1. 16c2−(a−5b)2.
  1. 4a2−(x+y)2.
  1. b2−(a−2x)2.
  1. 4z2−(x+3y)2.
  1. 9−(3a−7b)2.
  1. 16a2−(2b+5c)2.
  1. 25c2−(3a−2x)2.
  1. 9a2−(3b−5c)2.
  1. 16y2−(a−3c)2.
  1. 49m2−(p+2q)2.
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