CodalSearch this book — or all of Codal…⌘K
nydus/The First Steps in AlgebraPublic
Page 56 of 226
Table of Contents

Compound Integral Expressions.

  1. a+b+c and ac.
  1. a2ab+b2 and a2+b2.
  1. x33x2+7 and x23.
  1. a2+ab+b2 and ab.
  1. a2ab+b2 and a+b.
  1. x2+5x10 and 2x2+3x4.
  1. 3x32x2+x and 3x2+2x2.
  1. x3+2x2y+3xy2 and x22xy+y2.
  1. a23abb2 and a2+ab+2b2.
  1. 3a2b2+2ab35a3b and 5a2b2ab3b4.
  1. a22ab+b2 and a2+2ab+b2.
  1. ab+ac+cd and abac+cd.
  1. 3x2y2+xy32x3y and x2y2+xy33y4.
  1. x2+2xyy2 and x22xy+y2.
  1. 3x2+xyy2 and x22xy3y2.
  1. a22abb2 and b22aba2.
  1. a2+b2+c2ac and a2b2c2.
  1. a2+4abx4a2b2x2 and a24abx+4a2b2x2.
  1. 3a22abx+b2x2 and 2a2+3abx2b2x2.
  1. 2x3y+4x2y28xy3 and 2xy33x2y2+5x3y.

89. Division. Polynomials by Monomials.

lint Since a(b + c - d) = ab + ac - ad, ab + ac - ada = aba + aca - ada = b + c - d.

divide a polynomial by a monomial, therefore,

Divide each term of the dividend by the divisor, and add the partial quotients.

Divide 3a4b2c9a3bc26a2c3 by 3a2c.

3a4b2c9a3bc26a2c33a2c&=3a4b2c3a2c9a3bc23a2c6a2c33a2c&=a2b23abc2c2.

56