In the second question they will be placed thus:
20s. £20 15s. 25½ francs.
Reduce the first and second quantities, if necessary, to quantities of the same denomination. Thus, in the second question, £20 15s. must be reduced to shillings (219). The third quantity may also be reduced to any other denomination, if convenient; or the first and third may be multiplied by any quantity we please, as was done in the
second question; and, on looking at the answer in (238), and at (108), it will be seen that no change is made by that multiplication. Multiply the second and third quantities together, and divide by the first. The result is a quantity of the same sort as the third in the line, and is the answer required. Thus, to the first question the answer is (238)
| 208 × 156 | pence, or, which is the same thing, | 17 s. 4 d . × 156 | . |
|---|---|---|---|
| 22 | 22 |
- The whole process in the first question is as follows:15
- yds. yds. s. d.
- 22 : 156 ∷ 17 . 4
- 12
- 208 pence.
- 156
- 1248
- 1040
- 208
- 22)32448(1474¾d. and ¹⁴/₂₂, or ⁷/₁₁ of a farthing,
- 22 or (219) £6 . 2 . 10¾-⁷/₁₁.
- 104
- 88
- 164
- 154
- 108
- 88
- 20
- (228) 4
- 80
- 66
- 14
The question might have been solved without reducing 17s. 4d. to pence, thus:
- yds. yds. s. d.