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Integral Compound Expressions.

&2a3−3a2+2a−1−a3−2a2−3a+5&=2a3−a3−3a2−2a2+2a−3a−1+5&=a3−5a2−a+4.

This process is more easily performed by writing the subtrahend below the minuend, mentally changing the sign of each term in the subtrahend, and adding. r*3cr2a3&−&3a2&+&2a&−&1a3&+&2a2&+&3a&−&5\hlinea3&−&5a2&−&a&+&4

By changing the sign of each term in the subtrahend, the coefficient of a3 will be 2−1, or 1; the coefficient of a2 will be −3−2, or −5; the coefficient of a will be 2−3, or −1; the last term will be −1+5, or 4.

Again, suppose it is required to subtract x5−2ax4−3a2x3+4a3x2from4a3x2−2a2x3−5ax4. Here terms which are alike can be written in columns, as before: r*3cr&−&5ax4&−&2a2x3&+&4a3x2x5&−&2ax4&−&3a2x3&+&4a3x2\hline−x5&−&3ax4&+&a2x3&&

There is no term of x5 in the minuend, hence the coefficient of x5 in the result will be 0−1, or −1; the coefficient of ax4 will be −5+2, or −3; the coefficient of a2x3 will be −2+3, or +1; the coefficient of a3x2 will be −4+4, or 0, and therefore the term a3x2 will not appear in the result.

Exercise 19.

Subtract:

  1. a−2b+3c from 2a−3b+4c.
  1. a−3b−5c from 3a−5b+c.
  1. 2x−4y+6z from 4x−y−2z.
  1. 5x−11y−3z from 6x−7y+2z.
  1. ab−ac−bc+bd from ab+ac+bc+bd.
  1. 3ab+2ac−3bc+bd from 5ab−ac+bc+bd.
  1. 2x3−x2−5x+3 from 3x3+2x2−3x−5.
  1. 7x2−5x+1−a from x3−x+1−a.
  1. 7b3+8c3−15abc from 9b3+3abc−7c3.
  1. x4+x−5x3+5 from 7−2x2−3x3+x4.
  1. a3+b3+c3−3abc from 3abc+a3−2b3−3c3.
  1. 2x4−5x2+7x−3 from x4+2−2x3−x2.
  1. 1−x5−x+x4−x3 from x4+1+x+x2.
  1. a3−b3+3a2b−3ab2 from a3+b3−a2b−ab2.
  1. a2b−ab2−3a3b3−b4 from b4−5a3b3−2ab2+a2b.
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