Codal
nydus/The First Steps in AlgebraPublic
Page 56 of 226
Table of Contents

Compound Integral Expressions.

  1. a+b+c and a−c.
  1. a2−ab+b2 and a2+b2.
  1. x3−3x2+7 and x2−3.
  1. a2+ab+b2 and a−b.
  1. a2−ab+b2 and a+b.
  1. x2+5x−10 and 2x2+3x−4.
  1. 3x3−2x2+x and 3x2+2x−2.
  1. x3+2x2y+3xy2 and x2−2xy+y2.
  1. a2−3ab−b2 and −a2+ab+2b2.
  1. 3a2b2+2ab3−5a3b and 5a2b2−ab3−b4.
  1. a2−2ab+b2 and a2+2ab+b2.
  1. ab+ac+cd and ab−ac+cd.
  1. 3x2y2+xy3−2x3y and x2y2+xy3−3y4.
  1. x2+2xy−y2 and x2−2xy+y2.
  1. 3x2+xy−y2 and x2−2xy−3y2.
  1. a2−2ab−b2 and b2−2ab−a2.
  1. a2+b2+c2−ac and a2−b2−c2.
  1. a2+4abx−4a2b2x2 and a2−4abx+4a2b2x2.
  1. 3a2−2abx+b2x2 and 2a2+3abx−2b2x2.
  1. 2x3y+4x2y2−8xy3 and 2xy3−3x2y2+5x3y.

89. Division. Polynomials by Monomials.

lint Since a(b + c - d) = ab + ac - ad, ab + ac - ada = aba + aca - ada = b + c - d.

divide a polynomial by a monomial, therefore,

Divide each term of the dividend by the divisor, and add the partial quotients.

Divide 3a4b2c−9a3bc2−6a2c3 by 3a2c.

3a4b2c−9a3bc2−6a2c33a2c&=3a4b2c3a2c−9a3bc23a2c−6a2c33a2c&=a2b2−3abc−2c2.

56