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nydus/The First Steps in AlgebraPublic

This textbook introduces the fundamental concepts of algebra, including definitions of units, quantities, and number symbols. It explains the use of letters to represent numbers and outlines the signs for basic mathematical operations.

Page 53 of 227
Table of Contents

Compound Integral Expressions.

  1. 2x33x2+x and 2x2.
  1. a25abb2 and 5ab.
  1. a3+2a2b+2ab2 and a2.
  1. a3+2a2b+2ab2 and b3.
  1. 4x26xy9y2 and 2x.
  1. x22xy+y2 and y.
  1. a3a2b2b3 and a2.
  1. x2+2xyy2 and y2.
  1. 3a2b24ab3+a3b and 5a2b2.
  1. ax2+3axy2ay4 and 3ay2.
  1. x12x10y3x3y10 and x3y2.
  1. 2x3+3x2y22xy3 and 2x2y3.
  1. a3x2y5a2xy4ay3 and a7x3y5.
  1. 3a2b22ab3+5a3b and 5a2b3.

87. Multiplication. Polynomials by Polynomials.

If we have m+n+p to be multiplied by a+b+c, we may substitute M for the multiplier a+b+c. Then M(m+n+p)=Mm+Mn+Mp.

If now we substitute a+b+c for M, we shall have

find the product of two polynomials, therefore,

Multiply every term of the multiplicand by each term of the multiplier, and add the partial products.

In multiplying polynomials, it is a convenient arrangement to write the multiplier under the multiplicand, and place like terms of the partial products in columns.

  1. Multiply 2x3y by 5x4y. ccrrcr2x&&3&y&&5x&&4&y&&\cline1410x2&&15&xy&&&&8&xy&+&12y2\hline10x2&&23&xy&+&12y2

We multiply 2x, the first term of the multiplicand, by 5x, the first term of the multiplier, and obtain 10x2, then 3y, the second term of the multiplicand, by 5x, and obtain 15xy. The first line of partial products is 10x215xy. In multiplying by 4y, we obtain for a second line of partial products 8xy+12y2, which is put one place to the right, so that the like terms 15xy and 8xy may stand in the same column. We then add the coefficients of the like terms, and obtain the complete product in its simplest form.

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