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nydus/The Theory of Heat RadiationPublic
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Page 159 of 235
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138.

The thermodynamic state of the system of oscillators is fixed by the fact that the values of the distribution densities w1, w2, w3,  of the oscillators among the separate region elements are given. Within a region element the distribution of the oscillators is according to the law of elemental chaos ([sect:122.] Sec. 122), i.e., it is approximately uniform.

These data suffice for calculating the entropy S as well as the energy E of the system in the given state, the former quantity directly from [eqn:(173)] (173), the latter by the aid of [eqn:(205)] (205). It must be kept in mind in the calculation that, since the energy varies appreciably within a region element, the energy En of all those oscillators which lie in the nth region element is to be found by an integration. Then the whole energy E of the system is: E=E1+E2+En+.\Label[eqn](215)\upshape (215) En may be calculated with the help of the law that within every region element the oscillators are uniformly distributed. If the nth region element contains, all told, Nn oscillators, there are per unit area Nnh oscillators and hence Nnhdf·dψ per element of area. Hence we have: En=NnhUdfdψ. In performing the integration, instead of f and ψ we take C and ϕ, as new variables, and since according to [eqn:(211)] (211), f=Ccosϕψ=2πνLCsinϕ\Label[eqn](216)\upshape (216) we get: En=2πνLNnhUCdCdϕ to be integrated with respect to ϕ from 0 to 2π and with respect to C from Cn1 to Cn. If we substitute from [eqn:(205)] (205), [eqn:(209)] (209) and [eqn:(216)] (216) U=12KC2,\Label[eqn](217)\upshape (217) we obtain by integration En=π22νLKNnh(Cn4Cn14) and from [eqn:(214)] (214) and [eqn:(208)] (208): $E_{n} = N_{n}(n - \tfrac{1}{2})h\nu = Nw_{n}(n - \tfrac{1}{2})h\nu,

\Label[eqn]{(218)}\tag*{\upshape (218)}$ plus 0.75em minus 0.25em that is, the mean energy of an oscillator in the nth region element is (n12)hν. This is exactly the arithmetic mean of the energies (n1)hν and nhν which correspond to the two ellipses C=Cn1 and C=Cn bounding the region, as may be seen from [eqn:(217)] (217), if the values of Cn1 and Cn are therein substituted from [eqn:(214)] (214).

The total energy E is, according to [eqn:(215)] (215), E=Nhνn=1n=(n12)wn.\Label[eqn](219)\upshape (219)

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