Let us now consider briefly the phenomenon of scattering at thermodynamic equilibrium. Every ray meeting the volume-element suffers there, apart from absorption, a certain weakening of its intensity because a certain fraction of its energy is diverted in different directions. The value of the total energy of scattered radiation received and diverted, in the time by the volume-element in all directions, may be calculated from expression [eqn:(3)] (3) in exactly the same way as the value of the absorbed energy was calculated in [sect:26.] Sec. 26. Hence we get an expression similar to [eqn:(25)] (25), namely, The question as to what becomes of this energy is readily answered. On account of the isotropy of the medium, the energy scattered in and given by [eqn:(28)] (28) is radiated uniformly in all directions just as in the case of the energy entering . Hence that part of the scattered energy received in which is radiated out in a cone of solid angle is obtained by multiplying the last expression by . This gives and, for monochromatic plane polarized radiation,
Here it must be carefully kept in mind that this uniformity of radiation in all directions holds only for all rays striking the element taken together; a single ray, even in an isotropic medium, is scattered in different directions with different intensities and different directions of polarization. (See end of [sect:8.] Sec. 8.)
It is thus found that, when thermodynamic equilibrium of radiation exists inside of the medium, the process of scattering produces, on the whole, no effect. The radiation falling on a volume-element from all sides and scattered from it in all directions behaves exactly as if it had passed directly through the volume-element without the least modification. Every ray loses by scattering just as much energy as it regains by the scattering of other rays.