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nydus/The Theory of Heat RadiationPublic

This text examines the physical distinction between heat conduction and heat radiation, noting that radiation is independent of the medium through which it passes. It establishes that heat rays are physically identical to light rays and applies the principles of experimental optics to the study of thermal radiation.

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183.

It is now easy to state the relation of the two principles of thermodynamics to the irreversible processes here considered. Let us consider first the conservation of energy. If there is no oscillator in the field, every one of the elementary pencils, infinite in number, retains, during its rectilinear propagation, both its specific intensity 𝖪 and its energy without change, even though it be reflected at the surface, assumed as plane and reflecting, which bounds the field ([sect:166.] Sec. 166). The system of oscillators, on the other hand, produces a change in the incident pencils and hence also a change in the energy of the radiation propagated in the field. To calculate this we need consider only those monochromatic rays which lie close to the natural frequency ν of the oscillators, since the rest are not altered at all by the system.

The system is struck in the direction (θ,ϕ) within the conical element dΩ which converges toward the system of oscillators by a pencil polarized in some arbitrary way, the intensity of which is given by the sum of the two principal intensities 𝖪 and 𝖪'. This pencil, according to [sect:182.] Sec. 182, conveys the energy qΔν(𝖪+𝖪)dΩdt to the system in the time dt; hence this energy is taken from the field of radiation on the side of the rays arriving within dΩ. As a compensation there emerges from the system on the other side in the same direction (θ,ϕ) a pencil polarized in some definite way, the intensity of which is given by the sum of the two components 𝖪 and 𝖪. By it an amount of energy qΔν(𝖪+𝖪)dΩdt, is added to the field of radiation. Hence, all told, the change in energy of the field of radiation in the time dt is obtained by subtracting

the first expression from the second and by integrating with respect to dΩ. Thus we get dtΔν(𝖪+𝖪𝖪𝖪)qdΩ, or by taking account of [eqn:(330)] (330), [eqn:(335)] (335), and [eqn:(338)] (338) πNdtcLdΩsin2θ(𝖪e(𝖪cos2ψ+𝖪sin2ψ)).\Label[eqn](339)\upshape (339)

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